Mathematics 100 Online
OpenStudy (anonymous):

solve the inequality for x x^3-5x greater then or equal to 4x^2 i simplified to x(x+5)(x-1) but its saying that is incorrect

OpenStudy (anonymous):

$x^{3}-5x \ge 4x ^{2}$

OpenStudy (anonymous):

I'm solving hold on

OpenStudy (anonymous):

i figured it out and its $x(x-5)(x+1)$ how do i figure out which are included in the solution set

OpenStudy (anonymous):

$x^3-5x\geq 4x^2$ $x^3-4x^2-5x\geq0$ $x(x^2-4x-5)\geq 0$ $x(x+4)(x-5)\geq0$ zeros are at -4, 0 and 5and since this is a cubic polynomial with positive leading coefficient, it will be negative, then positive, then negative, then positive (think of the picture) you want it to be positive, so answer is $[-4,0]\cup [5,\infty)$

OpenStudy (anonymous):

OpenStudy (anonymous):

it says the answer is (-1,0] U [5, infinity)

OpenStudy (anonymous):

because if you factor out (x+4)(x-5) you get $x ^{2}-1x-30$ which isnt what i want

OpenStudy (anonymous):

solution x>=5 -1<=x<=0

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