Draw two triangles where A=30°, a=6,and b=10. Calculate and label the degree measure of each angle rounded to the nearest tenth.
Angle B=56.4 degrees. Angle C=93.6 degrees. Side C=12
This is a case for the law of sines, i believe we are trying to find the rest of the angles. You can set up the problem this way: a b 6 10 ---- = ------ further : ------- = ------, Simple cross multiply to get the answer. Sin A Sin B Sin 30 Sin B
Oh and rember to get the angle you have to do arch sine at the end
Then to get the last angle, simply subtract: 180-(sin A+sin B)=sin C
ty, I got correct answer now
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