Eliminate the parameter, t, and write a rectangular equation for
x =t^2 +3 and y = 2t.
fatema3151 (29 Aug 8:18 PM): i got t= sqrt of 3-x...i'm not sure where to go on from there

Question

Eliminate the parameter, t, and write a rectangular equation for 
x =t^2 +3 and y = 2t.
fatema3151 (29 Aug 8:18 PM): i got t= sqrt of 3-x...i'm not sure where to go on from there

anonymous · Answer

if $$X=t^{2}+3$$and$$Y=2t$$then solving for (t) in the last$$t=Y/2$$ substitute as (t) in the first$$X=(Y/2)^{2}+3$$and solve for Y$$Y=2\sqrt{X-3}$$good for any value of X equal or greater than 3, if is less than 3, the square root becomes negative and the values will be imaginary numbers.