factor completely: 360v^3-702v^2+324v=18v
some problem here because you wrote an equation with \[=18v\] on the right hand side. is that a typo?
no no typo
move the 18 v over and set it equal to 0 solve for a GCF and then factor the trinomial square
360v^3 -703v^2 +324v -18v =18v-18v=0
so what am i left with ?
360v^3-703v^2+306v=0 coefficients look coprime might have to synthetic divide are you familiar with this technique?
no
oh my mistake its 702 v^2 then take out an even greatest common factor
I thought you were done with this factoring stuff
not to be annoying but if it is set equal to something then the question should be "solve for v" not "factor"
v will have an actual value (or a choice of values) here. maybe you can solve by factoring
@hero i thought so too
lets factor out 18v
now i am wondering if it really did mean "factor" and ignore the right hand side, because the left hand side factors nicely as \[18 v (4 v-3) (5 v-6) = 18 v\]
whereas if you subtract 18v from both sides you get nothing very nice. where did the question come from?
a quiz
and it just said "factor" not "solve for v"?
yea it says factor completley
well tell your math teacher that if you have an equation, the only way for it to be true is if v takes on certain values. it really doesn't make sense to give an equation (something with an equal sign, like \[x^2-2x+1=5\] and say "factor"
like i guess paraenthisese are supposed to go after 18v
we know the obvious answer is v=0 the other factors are complex you could use the quadratic formula but i am too lazy :)
i need the quaratic formula
when given an quadratic equation of the form ax^2 +bx+c=0 where a,b,c are any elements of the reals, you can use x=(-b +/- sqrt(b^2-4ac))/2a
nevermiond lol i go it
You do?
what about 15h^2-17hj-4j^2
I'm done with doing these for right now
Oh, and Maria. Just a word of advice, you should get rid of the middle finger.
how about tht
about what?
the new picture
It's still the same from my end.
Oh nice. Much better :o)
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