Question

Solving quadratic equations... Can someone explain how to do this?
0 = x2 + 5x + 6
0 = x2 + 4x + 4
Answer not important... it's the how too. :) Thanks.

Answer 1

eliminate x2 by minusing second equation by the first
then solve for x

Answer 2

When solving a quadratic equation you should always make sure to set your equation to 0. Which in this case is already like that.

Next, you can either factor or use the quadratic formula. I'll just factor them out since it's easier that way.

x^2+5x+6 can be factored as (x+3)(x+2) which means x=-3 , x=-2
x^2+4x+4 can be factored as (x+2)(x+2) which means x=-2

Notice that if you multiply (x+3) and (x+2) you get x^2+5x+6 and you get x^2+4x+4 if you multiply (x+2) and (x+2). This is a good way to check your answers.

Answer 3

-b plus or minus the square root of (b2-4ac)
all of this divided by 2a
the formula you are basing this off ax2 + bx + c

Answer 4

then
2=x
checking
0=(-2)^2+4(-2)+4