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use the point slope form to write an equation of a line that passes through (3, -4) and is perpendicular to 2x-3y=5
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3x+2y=1
find m of 2x-3y=5 (rearrange equation in standard form) y=(2/3)x-(5/3) so m=2/3
solve the first equation in point slope form 2x-3y=5 where y = 2/3 x -5/3 Perpendicular slope you take the reciprocal and change the sign so your knew slope is m=-3/2
perperndicular lines have reciprocal gradient to that of the given since m=-2/3 then new equation will be y=(2/3)x-5/3
flip your slope remainder
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