Question

Find an equation of the line satisfying the conditions given. express your answer in standard form.

Parallel to 3x-y=-5 and passing through (-1,0)

Answer 1

y = 3x + b
0 = 3(-1) + b
b = 3
y = 3x + 3

Answer 2

in standard form
3x - y = 3

Answer 3

sorry its
3x - y = -3

Answer 4

parallel=same slope
all you have to do is put the point and slope in a point-slope equation.
slope of 3x-y=5:
-3x -3x
-y=5-3x
y=-5+3x
y=3x+5
so if y=mx+b and m is the slope, then the slope of that line is 3

plug that in with the point

y-0=3(x-(-1))
y=3(x+1)
y=3x+3

standard is :

y-3x=3
so -3x+y=3
but you can't have a negative in the front, so
3x-y=-3