Write the equation of the line parallel to x = -16 and passes through the point (9, -10).
parallel=same slope
y=-16x+b
-10=-16(9)+b. Solve for b
-10=-144+b 134=b
equation is x = -16 gandalfwiz not y = -16
:p me stupid
that's ok, the answer is actually x = 9 since this is also a vertical line but it passes through (9,-10)
how do you do this one? Write the equation of the line perpendicular to 9x + 2y = 18 and passes through the point (1, 4).
That's when you do it my way :). get your first equation into y=mx+b form, then follow my steps above
9x+2y=18 2y=-9x+18 y=-4.5x+9
perpendicular= negative reciprocal slope
The negative reciprocal is the number flipped upside down and multiplied by a negative.
-4 1/2=-9/2 2/9
Now u have y=2/9x+b
plug in your point for the y and x
4=2/9(1)+b 4=2/9+b 4-2/9=b
Since 4- 2/9 gives you tons of decimals, I'd leave it like that. Your equation is y=2/9x+(4- 2/9)
a. 9x - 2y = 1 b. 9x + 2y = 17 c. 2x - 9y = -34 d. 2x + 9y = 38
which one?
of course, you can combine 4-2/9 to get 34/9
choice C
another way to do it is swap the x and y coefficients and change the sign. From there, plug in x=1 and y=4 to find the right hand side
can you start from the beginning please i am so confused
sure, one sec
thanks :)
start with 9x + 2y = 18 ANY line perpendicular to this will be of the form 2x-9y = C where C is any number All I did here was swap the x and y coefficients 9 and 2 and then I changed the sign of the final y coefficient
So we now have 2x-9y = C Since this perpendicular line must go through (1,4), this means that x=1 and y=4 Plug these values in the equation above to get 2x-9y = C 2(1)-9(4) = C 2-36 = C -34 = C C = -34 So the equation of the perpendicular line that passes through (1,4) is 2x-9y = -34
does that make sense?
where did you get 1 and 4
from the point (1,4)
that the perpendicular line must pass through
o okay got it thanks!
great, np
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