Question

..can someone please help me with 4C and 4D on the first page?? n

Answer 1

Can someone please help!!

Answer 2

what coordinates did you get for A'B'C' ?

Answer 3

I didnt..i didnt understand it so i posted it on here...hoping u guys would help...

Answer 4

You asked for help with 4C and 4D. did you do 4A ?

Answer 5

yes.

Answer 6

what did you get ?

Answer 7

oh i got A' (-7,-3) B' (-3,-3) C' (-3,0)

Answer 8

for 4B - point reflection in the origin, I assume they mean a 180 degree rotation around the origin of each of the triangle's points.

http://en.wikipedia.org/wiki/Point_reflection

Answer 9

so is that right?

Answer 10

so,
A(-3,-7) --> A'(3,7)
B(-3,-3) --> B'(3,3)
C( 0,-3) --> C'(0,3)

Answer 11

for B)?

Answer 12

is that part B or part C?

Answer 13

the above is for 4B - where they ask about A'B'C'

Answer 14

Ok, but i need help with part C and Part D..

Answer 15

for part C, we should first have a diagram of part B. Can you draw it with the draw tool ?

Answer 16

i dont have that...but i didnt it on my graph paper, and it comes like a right triangle

Answer 17

*dd it

Answer 18

*did it

Answer 19

we will want to create a mirror image of the triangle A'B'C' using the horizontal line y=2

Answer 20

ya i got that part...

Answer 21

so what would be the coordinates?

Answer 22

so what did coordinates did you get for A'', B'', C'' ?

Answer 23

I got A'' (3,-3) B'' (3,1) C'' ( 0,1)

Answer 24

would that be it?

Answer 25

Did you use these coordinates A'(3,7) B'(3,3) C'(0,3)
To calculate A''B''C'' ?

Answer 26

i used the A'B'C' and i did y = 2 and reflected over it.

Answer 27

anyway, i'll just ask my teacher tommorow..thanks for helping

Answer 28

I'm just making sure we have the same coordinates for A'B'C' .
A'(3,7) B'(3,3) C'(0,3)

Answer 29

yep

Answer 30

OK,
A'(3,7) --> A''(3,-3)
B'(3,3) --> B''(3,1)
C'(0,3)--> C''(0,1)

That's what you got, right ?

Answer 31

for 4D T(-8,2):

A''(3,-3) -->A'''(-5,-1)
B''(3,1) -->B'''(-5,3)
C''(0,1) -->C'''(-8,3)