1.for non zero real nos: x and y the equality [x+y]^2 sec^2\[\theta\]=4xy is possible only when
a)x+y=1 b)x+y=-1 c)x-y=0 d)x+y=0
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OpenStudy (amistre64):
for non zero real nos: x and y the equality
[x+y]^2 sec^2(θ) = 4xy, hmmm
OpenStudy (amistre64):
we could back pedal into it to see maybe?
OpenStudy (aravindg):
???
OpenStudy (amistre64):
what is theta, anything?
OpenStudy (aravindg):
angle
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OpenStudy (amistre64):
good, cause i was thinking it might be been soup for a minute :)
OpenStudy (aravindg):
answer?
OpenStudy (amistre64):
i dunno an answer; but is sounds plausible that when x and y are opposites that you get a few zeros
OpenStudy (amistre64):
then again ....
OpenStudy (amistre64):
y = x; [x-x]^2 sec^2(θ) = 4x^2 not right
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OpenStudy (amistre64):
myin might be a good bet for doing these number bending stuffs
OpenStudy (aravindg):
???
OpenStudy (aravindg):
i neeed the answer
OpenStudy (amistre64):
openanswer.com is 3 doors down; this is more of a study group in my eyes
OpenStudy (amistre64):
at any rate, i got no answers for it, so good luck with it ;)
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OpenStudy (aravindg):
helppppp
OpenStudy (anonymous):
try wolfram alpha
OpenStudy (anonymous):
(not a user; a site)
OpenStudy (aravindg):
helpp
OpenStudy (anonymous):
i have no idea
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OpenStudy (anonymous):
from what topic or book does this question come?
OpenStudy (amistre64):
im assuming its the help me now i need an answer book; just a guess tho
OpenStudy (anonymous):
maybe it is the book of soup (none for you though)
myininaya (myininaya):
so it does not have to hold for all real x right?
it holds for some x that i see
if x=y,
then we have
(2x)^2sec^2(theta)=4x^2
4x^2sec^2(theta)=4x^2
and we know sec^2(theta) can be 1 sometimes since cos^2(theta) can be 1
OpenStudy (anonymous):
we can try
\[x=y\] right?
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OpenStudy (anonymous):
oh i am a little slow i see. hello myininaya
OpenStudy (anonymous):
yes i think for some values of theta x = y will work
myininaya (myininaya):
hey satellite
i'm tired
i think i'm gonna eat and watch tv
OpenStudy (anonymous):
oh you wrote that out too. ok done. since it says "only possible if" then you must be right.
is antiques roadshow on?
OpenStudy (anonymous):
now the question is, why not for any other value...
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OpenStudy (aravindg):
:(
OpenStudy (aravindg):
:(
OpenStudy (aravindg):
guys
OpenStudy (aravindg):
:(
OpenStudy (aravindg):
u cant answer?????
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