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solve 5^x=18. with steps to show how please
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there are in fact no real steps. to solve \[b^x=A\] for x you go right to the answer \[x=\frac{\ln(A)}{\ln(b)}\]
the only step is to take out your calculator and find that number. you can also use \[x=\frac{\log(A)}{\log(b)}\]
oh okay, so there's a formula. thanks a ton!
"log of the total divided by log of the base" some people call this the "change of base" formula but it is just how you solve
yes. and you can "derive" the formula if you like, it is not hard. but if i want to solve \[5^x=18\] i go right to \[x=\frac{\ln(18)}{\ln(5)}\]
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okay thanks!
yw
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