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Mathematics 17 Online
OpenStudy (ksaimouli):

solve x2+10x+21=0

OpenStudy (ksaimouli):

inn detail

OpenStudy (anonymous):

(x+7)(x+3)

OpenStudy (anonymous):

that is detail

OpenStudy (anonymous):

it's factoring....what numbers multiply to 21 and add to 10?

OpenStudy (anonymous):

7 and 3

OpenStudy (ksaimouli):

are u traporting 27

OpenStudy (anonymous):

where are you getting 27?

OpenStudy (ksaimouli):

they asked to solve but u

OpenStudy (anonymous):

well in order to solve it you have to factor it

OpenStudy (anonymous):

now you set each one equal to 0 and solve

OpenStudy (anonymous):

so it's x+7 = 0 and that answer is -7 by moving the 7 to the other side

OpenStudy (anonymous):

same with the other...answer is -3

OpenStudy (anonymous):

so your final answer is x = -7; x = -3

OpenStudy (anonymous):

x = (-b +- square root (b^2-4ac))/2a (any good calculator has this formula built in) x = 3 and 7. ie (x-3)(x-7). Since the product of these two numbers must be positive you have to have x < 3 (both values are negative) and x >7 (both values are positive). so 3 > x > 7

OpenStudy (anonymous):

that's the quadratic formula that is used only when you can't factor an equation

OpenStudy (anonymous):

this equation factors fine

OpenStudy (anonymous):

no u r wrong my answer is only correct

OpenStudy (anonymous):

lol..i'm not wrong...but okay...since you seem to know the answer already...really no point in asking here...good luck

OpenStudy (anonymous):

ok sorry gye

OpenStudy (anonymous):

OpenStudy (anonymous):

nice pic

OpenStudy (anonymous):

its nice nature ya correct

OpenStudy (anonymous):

OpenStudy (anonymous):

its nice or not mathballet

OpenStudy (anonymous):

u r telling nice

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