xz(2y+x-z) if x=2 y=5 and z=3
2*3(2*5+2-3 = 54
(2)(3)((2(5)+2-3)), evaluate that
xz(2y+x-z) 2*3(2*5+2-3) 2*3(10+2-3) 2*3(9) 54 So xz(2y+x-z) = 54 when x=2, y = 5 and z = 3
6(10+2-3)
why don't you do it yourself? It isn't difficult at all
maybe because i have a learning disability and what may be simple to you may nnot be for me. @fffeifei1
In between learning to tie his shoes and taking his ADD pills, he doesn't have much time to learn to manipulate simple operations.
what is that supposed to mean?
Ebnor please refrain from insulting others
Alright, alright... Sorry, Dan
and if you haven't learned this before, it might be difficult
the best thing to do is get familiar with the order of operations and PEMDAS
then go from there
Indeed. Practice and you'll be great at it
yes thank you. you know insults could deter a newcomer like me. btw thank you jim i graduated in '10 and i did this stuff in 10th grade. they only made me take one algebra class.
sounds odd since my experience saw that everyone needed at least 2 yrs of math, but oh well, guess every school is different but yeah, practice is the best way to learn and master math
so go over what I wrote above and ask any questions you have about any step
well i did take more than one math class. seinor year i ahd a choice of algebra 2 or liberal arts. you can guess which choose. second math class was geometry so i thank you. sometime this stuff is hard for me to grasp. i will def. look over and ask if needed.
ah I see, well that's good they gave you a choice
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