i need some help please
whats the question?
it would help tremendously if you could share the problem...
OO7<-------- This looks much cooler
-3+6x^10 find x2=x^2
Cheers Ishaan :)
Jesusluv, can you re-type the question, it's not quite clear. Thanks
^^^^^^^^^Agree
-3+6x^10
will someone please help me :)
Part of the issue facing us is interpreting what the question is...
is it find x ???
it's polynomials subsituting for x
Simply put, Jesusluv, we want to help...but you have to completely specify the question, otherwise we're all stuck
Are you able to type the question in full. Both words and equations/variables...Thanks
no im not
as far as i can see, u cant do too much w/ it.
u can factor out a 3
you guys know what polynimals are right?
yea but u never said what r supposed to do
Polynomials, algebraic equations, topology, calculus etc...
And I've asked you to type the question you want help with in full. And you seem reluctant
your supposed to do -3+6x^10 x=10 find x2=x^2
what do u mean by x2=x^2? u mean x^2=x^2 ?????
yes
Well said Mathballet! Jesusluv, C'mon, move those fingers...
ok undergrad007. do u agree with factoring a 3 as first step
I'm still trying to understand what task Jesusluv wants us to help with....
probably find x and square it
here go on coolmath .com and click algebra then once yuo get to algebra click exponents rule 1then go to plynomials
@undergrad- so what do u thnk
ok...You could have just provided the link to the webpage.... The lesson is about \[a ^{x} * a ^{y}\] and how you handle indices and such... Correct?
so would u factor it
@mathballet - I'm still lost
Assuming the question is about factoring, yes...I'd do so Mathballet :)
ok so im guessing its 3(1+(sqrt2)x^5)(1-(sqrt2)x^5)
what about u ??
I'll go along with whatever thoughts you have at this point mathballet. As Jesusluv, wants us to guess at the problem, rather than clearly state the matter at hand, He/She should be more than satisfied with your input. Welldone :)
yea we really had to pry it out didnt we
Quite so! Its a very strange experience "begging" for a problem that isn't ours to be explained so we can offer free help :D Best wishes to Mathballet & Jesusluv
thx :)
thank you for all your help:)
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