'Write an equation for the line that passes through (1, 5) and is PERPENDICULAR to the line -7x-5y=18" ?How do I do it?

Question

amistre64 · Answer

same thing ALMOST as a parallel; swap you numbers of x and y; and negate one of them; then fill in the point and change the constant

amistre64 · Answer

-7x-5y=18 ; swap numbers

-5x -7y=18 ; negate on of them, ill turn -5 into 5

5x -7y=18 ; now chop off the and and solve with the point given

5(1) -7(5 ) = N

amistre64 · Answer

care to take a try at what N will be?

anonymous · Answer

-30?

amistre64 · Answer

thats what I get too :)

soo....

5x - 7y = -30  is one way to write the equation of the perp.line

amistre64 · Answer

there are many "forms" that an equation can take, but they all amount to the same line

anonymous · Answer

I have ALOT of math questions be prepared :)

amistre64 · Answer

for instance:  all these are the same value

5x -7y = -30

-5x +7y = 30

y = (5/7)x + 30/7

and a few others