Pulley problem with three masses: m1, m2, m3 respectively. Massless string and pulley. Those are the equations I derived from newtowns law f = ma, and conservation of string. I'm not sure if the string that attaches the bottom pulley would have the same acceleration but in a opposite direction that might simplify the equation.

Question

anonymous · Answer

L1 + L 2 + L3 + L4 = 0
t - m1g = m1(L1)
t/2 - m2g = m2(L2)
t/2 - m3g = m3(L3)