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Mathematics 7 Online
OpenStudy (anonymous):

how do you simplify 6y^7)^4(12y^-5)^-3

OpenStudy (anonymous):

do you move (2y^-5)^-3 to the bottom and make it a fraction, or do u muliply the exponents -5 and -3 and they equal a positive so

OpenStudy (angela210793):

yea tht is sent in the denom cause it is in the -3<0 power

OpenStudy (anonymous):

so now we have (6y^7)^4 ? ___________ (12y^5)^3

OpenStudy (anonymous):

i meant (6y^7)^4/(12y^5)^3

OpenStudy (angela210793):

(6y^7)^4 __________ (12/y^5)^3

OpenStudy (anonymous):

multiply 2 exponents

OpenStudy (angela210793):

u see a^-x=1/a^x

OpenStudy (anonymous):

so do you take 6^4 power and add ^7 and ^4 coming up with 1296 y^28 power on top of the fraction?

OpenStudy (anonymous):

multiply ^7 and ^4 i mean

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so the answer should be 1296y^28/1728y^15 or do you do more to simplify it

OpenStudy (anonymous):

this is =(3/4)y^13 by using exponents rule

OpenStudy (anonymous):

okay ty

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