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find the domain in f(x)=x2+4
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All real numbers
show me algebracalliy
f(10)=10^2+4=104 .......f(0)=0^2+4=4 ...............f(-5)=(-5)^2+4=29.........you can put in any real number, f(-100000000).f(7),f(9999999) whatever you like
therefore the domain is any number your heart desires
Also, it is all real numbers because there is nothing that causes this to be 0
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since x^2 function is defined for all real x ..you can put anything in place of x and calculate x^2. so there is no restriction...it is obvious so no algebraic explanation has written -infinty < x < +infinity
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