simplify (5+x^-1)/(25-x^-2)
a=5 b=x^-1 a^2-b^2=(a+b)(a-b)
see if you can use the above, to get started.
@Fiddle r u saying tht (25-x^-2)=(5-x^-1)*(5+x^-1)?
answer my question
yes , do you agree ?
i thought it might b like tht too but wolfram says smth else http://www.wolframalpha.com/input/?i=%2825-x^-2%29
(5+1/x)/(25-1/x^2)
\[x \div(5x-1)\]
^_^
So wolfram treats both of the below the same way @angela: (25-x^-2) (5-x^-1)*(5+x^-1)
ignore my answers today...too hot outside :P
go to the dark side of the moon ! much cooler over there!
hahah...will do so :D
anyway - soccerchic do you need more help ? (I hope we didn't get you more confused)
Nope, i think i got it thanks for everyone's help :)
OK, if anything is still unclear - just ask here. If you are done with this question - don't forget to click the "Good Answer"s buttons :)
http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4e60e03a0b8b1f45b4a4777d
\[\frac{\frac{1}{x}+5}{25-\frac{1}{x^2}}=\frac{1}{5 (5 x-1)}+\frac{1}{5}=\frac{1}{25 x-5}+\frac{1}{5}=\frac{x}{5 x-1}\]
i could have sworn i answered this already
Yes, you did, so I gave you a medal.
\[-3\pm2\sqrt{5}\]
satellite - they only asked to simplify, not solve for x :)
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