Find an equation of the given line containing the given pair of points . (-8,-8) and (6,6) how do you do these problems
ok first u have to find the slope.. do u know how?
not really
ok here is the formula : (x1,y1) , (x2,y2) y2-y1/ x2-x1
now try using the points u have..
trying??
so it will be -8-6 then 6-8 right
no..
and it will be the same for both anyway.. b/c u have same points
ok see.. u have (-8,-8) (6,6) , just apply the formula u will get 6+8/6+8 14/14 1 do u get it? or not really?
do u need help
so im adding 6+8 which is 14 so the answer would be 14
yes its 14 but 14/14 is 1 right? do u agree??
Required eq. of line is: (y+8)/(6+8)=(x+8)/(6+8) =>y+8=x+8 =>y=x
ok u have a slope of 1 , now we want to find the line, i prefer using y=mx=b (or if u want u can use y-y1=m(x-x1) but now now we will use y=mx+b ok? y=mx+b ( u can choose any point u want from the 2 points) ill choose (6,6) (x,y) 6=1(6)+b 6=6+b b=0 (we found the y-intercept which is zero ao the equation is y=x
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