Question

x^2 – 16x + 15 = 0

Answer 1

first get the constant on the other side ....

x^2- 16x = -15

now take the half of the x-term and square it... then the square to both sides add it to both sides of the equation...

x^2- 16x+ 64x = -15 +64

simplify....

(x - 8 )^2 = 49

now take the square root of both sides....

( x - 8) = +or - 7

x= 15
x = 1

u can check the solution by plugging them back into the equation

hope this helps :)

Answer 2

(x-15)(x-1)=0

x=15 0r x =1