find 3 consecutive odd intergers such that 5 times the sum of the first and the third was 108 greater than twice the opposite of the number. help!!

Question

find 3 consecutive odd intergers such that 5 times  the sum of the first and the third was 108 greater than twice the opposite of the number.  help!!

anonymous · Answer

Say the first number is n then the next three are n+2 and n+4. So putting them into the equation in the question:
5(n + n + 4) = 108 + 2 ???
108 greater than twice the opposite of the number
The only part in the question I don't understand is what they mean by the opposite of the number.

anonymous · Answer

give me a min

anonymous · Answer

cant help you

anonymous · Answer

opposite of  a number means the  it's negative (e.g.: opposite of 5 is -5).
But not clear which number they mean.

anonymous · Answer

that's what I was confused about as well.

anonymous · Answer

Maybe they mean the number is:
5(2n+4)

anonymous · Answer

but that doesnt work out nicely