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a set of real numberssatifying the fiven inequality is one or more intervals abvalue x+pie/2 absvalue>1
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Find a range for x such that\[|x+\frac{\pi}{2}|>1\]Is that what you're asking?
I have to find the real nuymber satifying the give inequality
The inequality I posted above, you mean?
yes
All you have to do is solve for x in the equation: \[x+\frac{1}{2}\pi=1\]Simply enough: \[x=1-\frac{1}{2}\pi\]\[x=\frac{2-\pi}{2}\]But since we know that we're taking the absolute value, we find that \[(-\infty, \frac{2-\pi}{2})∪(\frac{2-\pi}{2}, \infty)\]is our range.
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I got the same thing thank you
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