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Physics 17 Online
OpenStudy (anonymous):

One gallon of paint (volume = 3.78 10-3 m3) covers an area of 20.0 m2. What is the thickness of the fresh paint on the wall?

OpenStudy (anonymous):

Well... just try thinking of it as a cuboid of paint with the volume 3.78 dm³ and a "base area" (don't know if that's the right term in english) of 20m²...

OpenStudy (anonymous):

You have a volume (gallon = 3.78x10^-3m^3) and another volume of which you only now is the area (20.0m^2) so:

OpenStudy (anonymous):

\[3.78x10^{-3} m^{3}=10m.2m.(X)m\]10m times 2m is 20m^2, solve for X and obtain the thickness of the coat.

OpenStudy (anonymous):

would it be 1.89 x 10^-4?

OpenStudy (anonymous):

im not entirely sure how to answer it

OpenStudy (anonymous):

thats what i got

OpenStudy (anonymous):

\[3.78x10^{-3} m^{3}/20m^{2}=Xm\]same as\[0.00378cubic-meters/20squar-meters=Xmeters\]same as\[0.00378/20=X\]

OpenStudy (anonymous):

Yep, 1.89x10^-4 = 0.000189meters

OpenStudy (anonymous):

yay!!! thank you so much!!!

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