3b^2-16b+16

Question

3b^2-16b+16

hero · Answer

3b^2 -12b - 4b + 16

3b(b-4) -4(b - 4)

(b-4)(3b - 4)

hero · Answer

Let me guess....You want to know how I did that, right?

anonymous · Answer

hahah yes if u dont mind ...where did u get 12b-4b from?

hero · Answer

Yes, that's the mysterious part. I must admit, if you want to do these as fast as me though, you have to be good. You have to practice....

hero · Answer

I will show you this once, and only once. Take notes

anonymous · Answer

lol ok

hero · Answer

Hopefully you already know stuff like a = 3, b = -16, c = 16

anonymous · Answer

yeah

hero · Answer

These formulas you absolutely have to memorize: 

|dw:1315105315684:dw|

Now, you can substitute a, b, and c, to find d: 
|dw:1315105428875:dw|

Notice I used difference of squares to get 48 = 64 - d^2

|dw:1315105565580:dw|

Subsitute d = +/- 4 back in to figure out what the factors are: 
|dw:1315105637414:dw|

These are your factors

That's it...and good luck. You can master that. It works even for prime and complex forms of the quadratic as well. To get as fast as me, you have to practice