Question

Find all solutions of 7x^4-42x^2-35x=0. I factored it to 7x(x^3-6x-5)=0 but can't get any farther without a graohing calculator.

Answer 1

7x(x+1)(x^2-x-5)

Answer 2

You can use the fundamental theorem of algebra

Answer 3

x=0 or x=-1then factorise
(x^2-x-5)using quadratic equation

Answer 4

(7x(x+1)(x-1)(x-5)

Answer 5

The fundamental theorem of algebra says I'll get 4 solutions, whether real or complex. How does that help me get to 7x(x+1)(x^2-x-5)? That's the step I'm missing.