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The formula r=2√5L can be used to approximate the speed r, in mph of a car that left skid marks of length L, in feet. How far will a car skid at 80 mph?
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r=2√5L 80=2√5L 40=√5L sq. both sides 1600=5L L=320
this is maybe (without exaggeration) the 8th time i have seen this exact same "skid marks" problem. one line class?
oh and look, it is the Math idol judge problem next. where are these coming from?
\[\large r=2\sqrt{5L}\] \[\large 80=2\sqrt{5L}\] \[\large \frac{80}{2}=\sqrt{5L}\] \[\large 40=\sqrt{5L}\] \[\large 40^2=5L\] \[\large 1600=5L\] \[\large \frac{1600}{5}=L\] \[\large 320=L\] \[\large L=320\] So the car will skid 320 ft.
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