Question

16x^2-16x-12 factor

Answer 1

Have you attempted to use my method for this?

Answer 2

Oh, actually, there was something I didn't tell you...

Answer 3

You have to first factor out what is common to each term first in this case....


Four is common to each factor so....

4(4x^2 - 4x - 3)

Answer 4

--> 4(4x^2 +2x -6x -3)
--> 4(2x(2x+1) -3(2x+1))
-->4(2x+1)(2x-3)

Answer 5

Ugh, I have no room for error with these.

Answer 6

I wrote down +2 when I did this on paper and still wrote -2 on here. I hate that