Question

find an equation of the line containing points (-4,1) and (2,-3)

Answer 1

First find the slope: (-3-1)/(2--4) => -4/6 = -2/3
Using y = mx + b substitute one point and the slope:
1 = -2/3(-4) + b
solve for b
1 = 8/3 + b
-5/3 = b
y = -2/3 x - 5/3

Answer 2

what you do is you use the slope formula

y2-y1
------
x2-x1

plug in the exponents like this:

-3-1
------
2-(-4) (leave-change-change)


=-4 /2
simplify: -2 (slope)
m=-2

y=-2x=b

substitite:

-3=-2(2)+b
-3=-4+b

add'4' to get b alone
four crosses out on the right

1=b


so then go back to the equation and you get

y=-2x+1

Answer 3

Izzy
2-(-4) ≠ 2