Question

how do i factor by grouping?

6x^2-x-15

Answer 1

Simplifying
6x2 + -1x + -15

Reorder the terms:
-15 + -1x + 6x2

Factor a trinomial.
(-3 + -2x)(5 + -3x)

Final result:
(-3 + -2x)(5 + -3x)

Answer 2

multiply
\[6\times -15=-90\] then see if you can find two numbers whose product is -90 and whose sum is -1

Answer 3

-10 , 9

Answer 4

those numbers are
\[-10,9\] so write
\[6x^2+9x-10x-15\] then factor each pair of terms
\[3x(2x+3)-5(2x+3)\]

Answer 5

you will see that you get one common factor when you do this, it is
\[(2x+3)\] in this case, so you can "factor it out" and write
\[(3x-5)(2x+3)\] those are all the steps, i think i didn't leave anything out

Answer 6

thanks for explaining :)

Answer 7

notice that the order was not important
you could have written it as
\[6x^2-10x+9x-15\]
\[2x(3x-5)+3(3x-5)\]

Answer 8

still get same answer
yw