Question

se the quadratic formula to solve...2x^2-x=-2. I get halfway through and lose the answer it sems

Answer 1

\[2x^2-x+2=0\] is a start, then use
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with
\[a=2,b=-1,c=2\] unless you think this one factors easily (i don't)

Answer 2

you get
\[\frac{1\pm\sqrt{1-4\times 2\times 2}}{2\times 2}=\frac{1\pm\sqrt{-15}}{4}\]

Answer 3

It doesn't, I spent forever on this

Answer 4

As far as factoring easily

Answer 5

which you can then write as
\[\frac{1}{4}-\frac{\sqrt{15}}{4}i\]and its conjugate
\[\frac{1}{4}+\frac{\sqrt{15}}{4}i\]