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Mathematics 7 Online
OpenStudy (anonymous):

∫(x+1)/x

OpenStudy (anonymous):

\[\int \frac{1+x}{x}dx \implies \int 1*dx + \frac{1}{x}dx\]

OpenStudy (anonymous):

okay why is the integral of 1/x, logx?

OpenStudy (anonymous):

Yup

OpenStudy (anonymous):

why?

OpenStudy (anonymous):

\[x + \log x + C\]

OpenStudy (anonymous):

hmm OKay No one asked me this before ....Let me give it a try ...wait a minute or you can think like in anti-derivative way Differentiation of \(\log x \) is \(\frac{1}{x}\) ...Hence Integral is \(\log x\)

OpenStudy (anonymous):

gotcha

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