Question

How do I find the set of zeros of f(x)=x^3+4x^2+4x?

Answer 1

x=0 is one zero
The other two you get by solving x^2+4x+4=0
(x+2)^2=0
x=-2 (twice)

Answer 2

where did you get zero from though?

Answer 3

f(x) = x (x+2)^2
so if x=0, f(x)=0(x+2)^2=0

Answer 4

All the addends in the expression are multiplied by x at least once