Estimate the limit numerically. (If the limit does not exist, enter NONE.)

lim x^2-10x+25 / x-5
x-5

I made a table with possible x values and solved using those. My table showed that as x approaches 5 the equation equals -25 . . . but that isn't the correct answer. Does the limit not exist then since it's negative?

Question

Estimate the limit numerically. (If the limit does not exist, enter NONE.)

lim   x^2-10x+25 / x-5  
x->5

I made a table with possible x values and solved using those.  My table showed that as x approaches 5 the equation equals -25 . . . but that isn't the correct answer.  Does the limit not exist then since it's negative?

anonymous · Answer

there is a hole in the graph at 5, so to find the limit you simplify the fraction
(x-5)(x-5)/(x-5)
lim=  x-5
x->5
now using teh substitution rule plug 5 in for x
lim=0
x->

anonymous · Answer

lim=(5-5)
x->5
lim=0
x->5
There that should look a little better

riley · Answer

Ohhhhh I see what you did there.  O_O  I didn't even consider simplifying and canceling out to find the limit.  Thank you so very much, that cleared everything up for me. =)

anonymous · Answer

Haha you are welcome.  I am glad it helped you.