Question

PLEASE PLEASE PLEASE HELP!!!! I'M BEGGING YOU!

1.The first differences of a sequence are a constant -7 and the third term is 22, find the first 5 terms of the sequence.

2.The third and fourth terms of a sequence are 101 and 83. If the first differences are constant, find the first 5 terms of the sequence.

3.For each sequence, determine which differences are constant and what the constant difference is.
a. 1, 2, 3, 4, 5, ...
b. 1^2, 2^2, 3^2, 4^2, 5^2, ...
c. 1^3, 2^3, 3^3, 4^3, 5^3, ...
d. Based on a, b, and c, determine how many differences you have to compute until

Answer 1

oops didn't finish

until you find a constant difference for the sequence 1^4, 2^4, 3^4, 4^4, 5^4, ...

Answer 2

1. 36,29,22,15,8
2. 137,119,101,83,65

Answer 3

um can you show me how to do it?

Answer 4

1 i worked back from 21 and added 7 until first term 36, then added -7 to 22 to get 4th term and another -7 to get 5th
2. difference between 101 and 83 = -18 so worked back as before by adding 18 to find 1st and second terms and added -18 to 83 o get fifth term

Answer 5

ok i understand that but the rest?

Answer 6

i'm confused by number 3
a - common difference is 1
b - these are squares of 1,2,3,4 ...
= 1,4,9,16,25 - difference is increasing
c - cubes - increasing
d - 4th power - increasing

Answer 7

im confused..

Answer 8

the only constant difference in b,c,d is the base numbers 1,2,3,4,5....

Answer 9

uh..