Question

I'm trying to find the square root for this
(4y+6)^2=36

Answer 1

divide of the 4 and subtract the 6

Answer 2

or y = 0 for one

Answer 3

-3 for the other?

Answer 4

divide the 4 by what?

Answer 5

nothing, i was reading a different problem in my head :)

Answer 6

oh

Answer 7

if we sqrt the sides we get:

4y+6 = +- 6

Answer 8

4y+6 = 6 ===> y=0 or 4y+6 = -6 ==> y=12/4=3

Answer 9

I mean y =-12/4=-3

Answer 10

4y+6 = +- 6
-6 -6
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4y = 0 , -12
/4 /4
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y = 0, -3