Question

Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function and graph the function:
f(x)= -2x^2+2x+1

Answer 1

Let's start with the vertex-

Once you get to calc, you'll be able to solve for the point at which the derivative of the function is 0. But until then, take my word that any equation in the form f(x)= ax^2 + bx +c will have its vertex at (-b/2a, f(-b/2a)). In this equation, that would be 1/2. When you plug 1/2 back into the function, you should get 3/2. Because the vertex of a quadratic functions y value is always the max/min, 3/2 will be the max, in this case, because the function points down.

Answer 2

so the vertex is 1/2?