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Mathematics 22 Online
OpenStudy (anonymous):

find the point (x,0) that is equidistant from the points (6,1) and (-2,5)

OpenStudy (anonymous):

What you do is find the average value between each x and y value. In this case, you would take each x-value, 6 and -2, add them up and divide by two to find the average, which ends up being 2. That's the x coordinate for your point equidistant from both points. You would do the same thing with the y-values (1+5=6, 6/2=3) and that would be your y-value. Put the two together as a coordinate pair, and you have your point: (2,3)

OpenStudy (anonymous):

thanks!

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