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solve 2x^2=10 and find x intercepts of f(x)=2x^2-10
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Divide each side by 2 2x^2/2 = 10/2 x^2 = 5 square root (x^2) = square root (5) x = +/- (square root) 5
ok and what about the x intercepts?
You create a table and insert for x X| 1 | 2 | 3 | 4 | 5 | Y| -6| 6| etc.....
I don't get it
here it shows a graph im going to put it up maybe you can help
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2x^2=10 ===> x^2 = 10/2 =5 ===> x= sqrt(5) or x=-sqrt(5)
btw sqrt(5) = 2.24
ok and can you give me the x intercepts?
what we solved are the x-intercept
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so its (0,2.24)
no
solve 2x^2=10 and find x intercepts of f(x)=2x^2-10
swich the coordinates ( sqrt(5),0) =(2.24,0) , (-sqrt(5),0)=(-2.24,0)
oh ok
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hope this helps.
Thanks
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