Question

Are 6ab and 4ba like terms? I don't think it is because the variables are in a different order.

Answer 1

yes they are.

6ab = 6ba
and
4ba=4ab

Answer 2

yea,, because even though they are in a seprate order they sill end up equaling the same outcome

Answer 3

6ab means 6*a*b
6ba means 6*b*a

Same thing.

Answer 4

Omg it's FIDDLE!!!!!! xD

Answer 5

Correcto!

Answer 6

I'll give you a medal for noticing it's me shall I ?

Answer 7

Ok, thank you. I wasn't sure. Btw how are the both of you? :)

Answer 8

both of us ?

Answer 9

Ok, Fiddle. :)

Answer 10

does it make sense - this whole business with
6ab being the same as 6ba ?

Answer 11

Yes they are like terms

Answer 12

Yup, I was just confused because I haven't been doing these in a while.

Answer 13

OK. So all the below are the same:

5bag = 5gba = 5abg

But, the convention is to write the term with the number in front,
then the letters, sorted according to alphabetical order:
So if we get something like

5bag

We would write it as

5abg

That way if we always write terms like this - it will be pretty
easy to identify like terms.

5bag and 8gab are like terms coz
5abg and 8abg (the same terms) are like terms.

Answer 14

so do you like terms after all this ?

Answer 15

Yup, as long as it is not a fraction.

Answer 16

I'm sory for replying so long. I'm using the school computer and it takes a minute or so to do something.

Answer 17

can you give an example of a fraction you really don't like - and explain what you don't like about it ?

Answer 18

Um....actually I'm having problems with this hw problem and I have to write out the algebraic model and also solve it with mental math. The algebraic model has a fraction bar and I'm really lost. But heres the sentence/problem: You are given $75 to buy juice for the school dance. Each bottle of juice costs $.75. Write a verbal and an algebraic model to find how many bottles of juice you can buy. Write an equation and use mental math to solve the equation.
I got 100 juice as my answer, am I right Fiddle?