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2sqrt{x-1}+1=x
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* 4x-4 = x^2 * x^2 - 4x + 4 = 0 (Can you go now?)
nope lol
* Just remember to discard the negative solution about x
* Just remember to discard the negative solution about x because I think you are using the Real set of numbers and in this universe, sqrt is just for non negative numbers!
so the answer cant be negative?
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x needs be 1 or greater than 1, because sqrt is just to zero or greater than zero, did you understand?
oh ok
so, if you try, you will find x1 = 0 and x2 = 2... so, as I said, which is our x?
2?
Yes!!! Congratulations!!!!
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lol thnx
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