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Mathematics 21 Online
OpenStudy (anonymous):

2sqrt{x-1}+1=x

OpenStudy (anonymous):

* 4x-4 = x^2 * x^2 - 4x + 4 = 0 (Can you go now?)

OpenStudy (anonymous):

nope lol

OpenStudy (anonymous):

* Just remember to discard the negative solution about x

OpenStudy (anonymous):

* Just remember to discard the negative solution about x because I think you are using the Real set of numbers and in this universe, sqrt is just for non negative numbers!

OpenStudy (anonymous):

so the answer cant be negative?

OpenStudy (anonymous):

x needs be 1 or greater than 1, because sqrt is just to zero or greater than zero, did you understand?

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

so, if you try, you will find x1 = 0 and x2 = 2... so, as I said, which is our x?

OpenStudy (anonymous):

2?

OpenStudy (anonymous):

Yes!!! Congratulations!!!!

OpenStudy (anonymous):

lol thnx

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