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Mathematics 18 Online
OpenStudy (anonymous):

3sqrt{x-1}+1=x

OpenStudy (anonymous):

draw it out please.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

\[3\sqrt{x-1}+1=x\]

OpenStudy (anonymous):

(x-10)*(x-1)=0 x=10 or 1.

OpenStudy (anonymous):

actually, just say its 10. If you plug in 10 for x, you'll get it to be correct.

OpenStudy (anonymous):

no its not right

OpenStudy (anonymous):

\[3\sqrt{x-1}+1=x\] \[3\sqrt{x-1}=x-1\] squaring on both sides \[(3\sqrt{x-1})^2=(x-1)^2\] \[9(x-1)=x^2-2x+1\] \[9x-9=x^2-2x+1\] \[x^2-2x-9x+1+9=0\] \[x^2-11x+10=0\] \[x^2-10x-x+10=0\] \[x(x-10)-1(x-10)=0\] \[(x-1)(x-10)=0\] \[x=1,x=10\]

OpenStudy (anonymous):

u want to do another one?

OpenStudy (anonymous):

I am right...

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