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3sqrt{x-1}+1=x
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draw it out please.
ok
\[3\sqrt{x-1}+1=x\]
(x-10)*(x-1)=0 x=10 or 1.
actually, just say its 10. If you plug in 10 for x, you'll get it to be correct.
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no its not right
\[3\sqrt{x-1}+1=x\] \[3\sqrt{x-1}=x-1\] squaring on both sides \[(3\sqrt{x-1})^2=(x-1)^2\] \[9(x-1)=x^2-2x+1\] \[9x-9=x^2-2x+1\] \[x^2-2x-9x+1+9=0\] \[x^2-11x+10=0\] \[x^2-10x-x+10=0\] \[x(x-10)-1(x-10)=0\] \[(x-1)(x-10)=0\] \[x=1,x=10\]
u want to do another one?
I am right...
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