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give a rigorous proof that f(x)= x^2+3x is continous at x=2
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f(2) = 4+6=10 , lim f(x) [when x___> 2 ] = 4+6 =10 , ===> f(x) is continous at x=2
when it says rigorous proof, you hae to show it by using epsilon and delta :P
|dw:1315459646675:dw| there's only 1 point on the line when x=2 which makes it continuous right?
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