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Mathematics 18 Online
OpenStudy (anonymous):

How do you show that nC0 and nCn always = 1

OpenStudy (anonymous):

remember nCk = n!/(n-k!)k! just do two cases: 1. let k = n 2. let k = 0 Dont forget that 0! = 1 (guess that's a more complete answer)

OpenStudy (anonymous):

actually ill plug it in too nC0 = n!/(n!*0!)=n!/n!=1 nCn = n!/(0!*n!)=n!/n!=1

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