Question

A boat travels 3 hrs. with a current at a speed at 10kph and returns the same distance against the current an hour home. Determine the boat's speed in still water.

Answer 1

when you say 'an hour home' what do you mean?

Answer 2

by the way, it you return to the question about 2 numbers adding up to 114 i can explain how to do it

Answer 3

yes, pls explain:))

Answer 4

ok i'll go there now

Answer 5

ok

Answer 6

right i've left an explanation in that post - though it took a while the system just went into crawl mode.

Answer 7

let speed of boat = s
speed of current = 10 kph
d= distance travelled
speed of boat along current s1 = s+10
time t1 = 3hours

so distance traveled d1 = speed*time = (s+10)*3 = 3(s+10)=3s+30 -----(I)

speed of boat against current s2 = s-10
time t2 = 4 hours

so distance traveled d2 = speed*time = (s-10)*4 = 4(s-10)=4s-40 -----(II)

but d1=d2 ( as same distance is traveled in both directions)

so 3s+30 = 4s-40

so s=70

so the boat's speed in still water is 70 kph