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Find \[\int\limits_{C}^{}\frac{1}{e^{z}(z-2)}dz\] and C is the ellipse \[\frac{x^{2}}{9}+\frac{y^{2}}{16}=1\]
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i know the cauchy integral formula, http://en.wikipedia.org/wiki/Cauchy's_integral_formula
is my f(z) =e^-z ???
then a=+2 maybe
*bookmark* :D
is complexifying it better maybe?
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rearranging the CIF we get 2pi*i*f(a)= integral ......
maybe its easier then i thought
2pi*e^-2*i
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