A bag contains 7 lavender marbles, 11 turquoise marbles and 5 rainbow marbles. What is the chance of drawing a turquoise marble? If a turquoise marble is drawn then placed back into the bag, and a second marble is drawn, what is the probability of drawing a rainbow marble? Give solutions exactly in reduced fraction form, separated by a comma.

Question

anonymous · Answer

There is an 11/23 chance of picking a turquoise marble from the whole lot the first time. There is a 5/23 chance that the second marble drawn is rainbow.$${11\over23},{5\over23}$$

anonymous · Answer

total=7+11+5=23
p(turquoise marble) =  turquoise marbles/total marbles
=11/23
p(rainbow marble) =  rainbow marbles/total marbles
=5/23

11/23,5/23

anonymous · Answer

as a matter of interest the chance of getting a turquoise then a rainbow is obtained by multiplying the 2 results
i.e.       11/23   *   5/23