State the domain and range
(Please, when you do it, don't just give me an answer, that doesn't help. Show your work)

y=-2(x+1)^2-3

Question

State the domain and range 
(Please, when you do it, don't just give me an answer, that doesn't help. Show your work)

y=-2(x+1)^2-3

anonymous · Answer

This is standard form for a quadratic polynomial function.  The domain for any polynomial function is all real numbers.

anonymous · Answer

Alright, so whats the range?

anonymous · Answer

Anything can go into the function right? So the domain is real.
The squared function only gives out positive numbers, the sign is changed by the output of -2(x+1)^2 is negative for real x. The -3 then means that all output values are then equal to or less than -3.
So in summary, the domain is real and the range is y <= -3

anonymous · Answer

Hopefully that's slightly understandable..

anonymous · Answer

The standard form looks like$$y=a(x-h)^2+k$$where (h,k) is the vertex of the parabola (which is the shape of the graph of the function).  When a is negative as in your case the parabola opens downward (see drawing) and the vertex is (-1, -3).  The range is all y values less than or equal to -3.|dw:1315529364812:dw|