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what is the answer for this? 4x - 3y = 1 2x + 9y = 4
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multiply the first equation by 3 (4x - 3y = 1)3------>12x-9y=3 now add both equations 12x-9y=3 +2x+9y=4 ----------- 14x=7 x=7/14=1/2 now plug x value into one of the equation 2(1/2)+9y=4 1+9y=4 9y=4-1 y=3/9=1/3 so x=1/2 and y=1/3
why 3?
\[y=\frac{1}{3}\] not 3
thanks
yw :)
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\[a ^{2} x a ^{3} x a ^{-2}/ a ^{-3} x a ^{6}= how about this one please?
\[\frac{a^{2+3-2}}{a^{-3+6}}\] \[\frac{a^3}{a^3}=1\]
thanks
24x ^{3} y ^{2} z ^{3}/ 4x ^{2} yz ^{2}= ?? help
\[x ^{3} y ^{2} x ^{5} + 2x ^{7} y ^{-4} xy ^{6}\]
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