Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (anonymous):

DECILES the deciles of any distribution at the points tht mark off the lowest 10% and the highest 10%. The deciles of a density curve are therefore the points with are 0.1 and 0.9 to their left under the curve. a) What are the declies of the standard Normal distribution? b) The heights of young women are approximately Normal with mean 64.5 inches and standard deviation 2.5 inches. what are the declies of this distribution? show your work

OpenStudy (amistre64):

decilies are every 10%

OpenStudy (amistre64):

hmm .... and area of 1% under the curve eh

OpenStudy (amistre64):

"therefore the points with are 0.1 and 0.9 to their left under the curve" this part almost makes sense .... can you clarify it?

OpenStudy (amistre64):

it looks like you want the zscore associated with 10%

OpenStudy (amistre64):

your best bet, if you aint got a calculator that does the invNorm(%) is tho use the ztable in the back of a book

OpenStudy (anonymous):

i have a ti 84

OpenStudy (amistre64):

thatll work :) hit 2nd and vars to get the distribution menu

OpenStudy (amistre64):

scroll down and you should see the "invNorm()" function

OpenStudy (anonymous):

what i do next?

OpenStudy (amistre64):

type in (.1,mean,sd) ; since its a normal distribution the mean = 0 and the sd = 1 invnorm(.1,0,1)

OpenStudy (amistre64):

then it should give you a number close to 1.282

OpenStudy (anonymous):

i got a negative

OpenStudy (amistre64):

thats fine ...

OpenStudy (anonymous):

ok is the mean always 0

OpenStudy (amistre64):

|dw:1315534791327:dw|

OpenStudy (amistre64):

nope, the mean changes and so does the standard deviation (sd) as you can see in the next problem

OpenStudy (amistre64):

unless stated, the mean is 0 and the sd is 1

OpenStudy (amistre64):

the mean is the line i drew in the middle of the humpback; you have -zscores to the left and + zscores to the right

OpenStudy (amistre64):

the zscore for 10% = what, -1.282 or so?

OpenStudy (anonymous):

i got that

OpenStudy (amistre64):

the zscore for 90% then is just the postive of that

OpenStudy (amistre64):

The heights of young women are approximately Normal with mean 64.5 inches and standard deviation 2.5 inches. what are the declies of this distribution? show your work now for this one its the same thing, but mean = 64.5 and sd = 2.5

OpenStudy (amistre64):

invnorm(.1,64.5,2.5) = zscore

OpenStudy (anonymous):

is it 61?

OpenStudy (amistre64):

close enough :)

OpenStudy (amistre64):

now plug in .9 for the other one since we aint circling about a 0mean anymore

OpenStudy (amistre64):

should give you about 68 for the 90%

OpenStudy (anonymous):

thank you teach better than my tracher

OpenStudy (anonymous):

teacher*

OpenStudy (amistre64):

when i was going thru it during the summer term in college, my teacher was pretty much running thru it like it was on fire ...

OpenStudy (anonymous):

my teacher just shows us magic tricks instead of teaching the lesson

OpenStudy (amistre64):

lol .... chris angel is teaching your class?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!